Composite base material for drinking water biological treatment and method for using the same
A composite matrix and quality technology, applied in water/sewage treatment, water/sludge/sewage treatment, flocculation/sedimentation water/sewage treatment, etc., can solve the problems of poor biodegradability, incomplete development and low proportion, etc. Achieve the effect of improving biological stability, good industrial prospects, and promoting removal
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Embodiment 1
[0033] The influent of a biological pretreatment reactor is 50,000m 3 / day, BDOC concentration is 0.5mg / L, BDOC: DOC=0.05, P is the main limiting factor, the amount of organic matter that is expected to be added is 1 / 15 of BDOC (0.5 / 15=0.033mg / L=33μg / L), the dosage of composite matrix is controlled at 300L / d, then the preparation concentration of composite matrix solution can be calculated as follows:
[0034] The total amount of matrix added per day is calculated in C = 50,000m 3 / day×33μg / L=1650g / day.
[0035] Then, 1650g / day=300L / d×composite matrix concentration
[0036] Composite matrix concentration = 1650g / day ÷ 300L / day = 5.5g / L
[0037] According to Table 1, the specific composition of the composite matrix: Glucose-C 0g / L; Acetate-C, 5.5g / L; Phosphate-P, 1.1g / L. According to the treatment effect, the adjustable range is Glucose-C 0 ~1.65g / L; Acetate-C, 4.4~6.6g / L; Phosphate-P, 0.55~1.65g / L.
[0038] Composite matrix is prepared according to the ratio in Table...
Embodiment 2
[0040] A biologically active filter with an inflow flow of 5,000m 3 / day, BDOC concentration is 0.6mg / L, BDOC:DOC=0.15, P is the main limiting factor, the amount of organic matter that is expected to be added is 1 / 15 of BDOC (0.6 / 15=0.04mg / L=40μg / L), the dosage of composite matrix is controlled at 200L / d, then the preparation concentration of composite matrix solution can be calculated as follows:
[0041] The total amount of matrix added per day is calculated in C = 5,000m 3 / day×40μg / L=200g / day.
[0042] Then, 200g / day=200L / d×composite matrix concentration
[0043] Composite matrix concentration = 200g / day ÷ 200L / day = 1g / L
[0044] According to Table 1, the specific composition of the composite matrix: glucose-C, 0.3g / L; acetate-C, 0.7g / L; phosphate-P, 0.2g / L; according to the treatment effect, the range that can be adjusted is glucose- C 0.1~0.5g / L; Acetate-C, 0.5~0.9g / L; Phosphate-P, 0.1~0.3g / L.
[0045] For this bioactive filter, the composite matrix is prepare...
Embodiment 3
[0047] A biological pretreatment reactor feed water flow rate of 400,000m 3 / day, BDOC concentration is 0.75mg / L, P is the main limiting factor, BDOC:DOC=0.25, the amount of organic matter to be added is 1 / 15 of BDOC (0.75 / 15=0.05mg / L=50μg / L), and the dosage of the composite matrix is controlled at 500L / d, then the concentration of the composite matrix solution can be calculated as follows:
[0048] The total amount of matrix added per day is calculated in C = 400,000m 3 / day×50μg / L=20,000g / day.
[0049] Then, 20,000g / day=500L / d×composite matrix concentration
[0050] Composite matrix concentration = 20,000g / day ÷ 500L / day = 40g / L
[0051] According to Table 1, the specific composition of the composite matrix: Glucose-C, 28g / L; Acetate-C, 12g / L; Phosphate-P, 8g / L; according to the treatment effect, the adjustable range is Glucose-C 20~ 36g / L; Acetate-C, 4~20g / L; Phosphate-P, 4~12g / L.
[0052] For this biological pretreatment reactor, the composite matrix is prepared ...
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