Method for measuring oxygen content in iron powder
A technology of oxygen content and measurement method, applied in the field of measurement, can solve the problems of high cost, rust, easy damping of iron powder, etc., and achieve the effect of convenient operation and economical operation.
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Embodiment 1
[0014] Example 1: The batch number 1211147 Jiande Yitong 300W water atomized iron powder purchased on November 24, 2012 was tested, and the result was that the oxygen content was 0.04%. Conform to the standard: oxygen content <0.2% (executive standard: Q / YTJ001-2009), the specific steps are as follows:
[0015] (1) Take a bag of iron powder (1 ton) and sample three places, weigh 50g each, and then mix according to the ratio: graphite powder 0.5g, iron powder 49.5g.
[0016] (2) After mixing, weigh 1.000g on a precision balance, and measure the carbon content on a carbon and sulfur analyzer: 0.630%, 0.560%, and 0.595%
[0017] Average X 1 =(0.630%+0.560%+0.595%)÷3=0.595%
[0018] Carbon segregation=0.630%-0.595%=0.035%, carbon segregation is within 0.1%, qualified.
[0019] (3) Put the three groups of mixed powder into the mold respectively, and press it into a green compact with a diameter of φ20 and a height of 15mm on a material testing machine.
[0020] (4) Sintering in...
Embodiment 2
[0024] Example 2: 13 tons of 100-mesh reduced iron powder purchased on November 28, 2012 without the name of the manufacturer was tested, and the result was that the oxygen content was 0.676%. According to the national standard GB / T4136-1994: the oxygen content of the brand FHY100.25 reduced iron powder is less than 0.3%, and this batch of iron powder seriously exceeds the standard. The specific steps are as follows:
[0025] (1) Take a bag of iron powder (1 ton) and sample three places, weigh 50g each, and then mix according to the ratio: graphite powder 0.5g, iron powder 49.5g.
[0026] (2) After mixing, weigh 1.000g on a precision balance, and measure the carbon content on a carbon and sulfur analyzer: 0.720%, 0.700%, and 0.650%
[0027] Average X 1 =(0.720%+0.700%+0.650%)÷3=0.690%
[0028] Carbon segregation=0.720%-0.690%=0.03%, carbon segregation is within 0.1%, qualified.
[0029] (3) The three groups of mixed powders were put into the mold respectively, and pressed i...
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