Current based open-circuit fault detection method for three-phase inverter
A three-phase inverter, open-circuit fault technology, applied in the direction of measuring electrical variables, instruments, measuring electricity, etc., can solve the problems of excessive calculation, increased calculation amount, slow detection, etc., to achieve small overall calculation amount, fast speed, avoidance of The effect of false alarms
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[0044] figure 2 It is a flow chart of the current-based three-phase inverter open-circuit fault detection method of the present invention.
[0045] In this example, if figure 2 As shown, the current-based three-phase inverter open-circuit fault detection method of the present invention comprises the following steps:
[0046] (1), Obtain the motor three-phase current i from the motor drive control system n (n = a, b, c);
[0047] (2), according to the motor three-phase current i n Calculate the detection variable d of each phase n (n=a,b,c)
[0048] d n = 3 ( | i n | > - 2 i n > ) ...
example
[0063] In this embodiment, it is assumed that the rated power of the three-phase AC asynchronous motor is 1.1kW, the rated speed is 1390rpm, the rated torque is 7.6Nm, the rated current is 2.89A, and the detection variable threshold k 1 =-0.3,k 2 =0.3,k 3 = 1.8,k 4 = 3.3.
[0064] image 3 is the three-phase current of the motor and the detection variable d n waveform diagram.
[0065] In this example, if image 3 As shown, when the motor is at rated speed and 50% rated load, at time t=2s, T1 has an open-circuit fault; at t=2.2s, T1 and T2 have open-circuit faults at the same time; at t=2.4s, T1, T2 and T3 simultaneously open-circuit fault; the details are as follows:
[0066] When t=1.8~2s:
[0067] Such as image 3 As shown in (a), the motor phase current i a is a symmetrical sine wave, then d a ≈1, fault indication D a = 0; if image 3 As shown in (b), the motor phase current i b is a symmetrical sine wave, then d b ≈1, fault indication D b = 0; if image 3...
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