Method for improving standard shuffled frog leaping algorithm
A hybrid leapfrog algorithm, standard technology, applied in the field of improved standard hybrid leapfrog algorithm, can solve the problems of falling into local optimum, slowing down of convergence speed, insufficient convergence accuracy, etc.
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Embodiment 1
[0072] The purpose of this embodiment is to verify the convergence accuracy.
[0073]The technical solution adopted in this embodiment to solve this technical problem is: a method for improving the standard hybrid leapfrog algorithm, which combines the population mixing mechanism in the standard hybrid leapfrog algorithm with the internal iteration mechanism of the subpopulation, and dynamically Adjust the moving step length, and realize the improved algorithm by means of MicrosoftVisualC++ computer software. The specific steps are as follows:
[0074] The first step is to determine the parameters that need to be initialized and their initial values:
[0075] Referring to the parameter initialization of the standard hybrid leapfrog algorithm, determine the parameters that need to be initialized after the improved hybrid leapfrog algorithm, including: the number of individuals F of the frog population, the number of frog subpopulations m, the number of frog individuals n of eac...
Embodiment 2
[0138] The purpose of this embodiment is to verify the convergence success rate.
[0139] The technical solution adopted in this embodiment to solve this technical problem is: a method for improving the standard hybrid leapfrog algorithm, which combines the population mixing mechanism in the standard hybrid leapfrog algorithm with the internal iteration mechanism of the subpopulation, and dynamically Adjust the moving step length, and realize the improved algorithm by means of MicrosoftVisualC++ computer software. The specific steps are as follows:
[0140] The first step is to determine the parameters that need to be initialized and their initial values:
[0141] Except the following data, others are the same as Example 1.
[0142] The number of individuals in the frog population F=48, the number of frog subpopulations m=8, the number of frogs in each frog subpopulation n=6, the position of each frog individual X i ={x i1 , x i2}, maximum number of mixing iterations N=80×...
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