A method for calculating loss quantity of exponential unit spare parts
A calculation method, an exponential technology, applied in the direction of calculation, data processing applications, instruments, etc., can solve the problems of spare parts guarantee effect without considering the loss of spare parts, not in line with the actual situation, unable to accurately reflect the cost of spare parts, etc., to achieve fast and convenient calculation, The error is small and the effect of meeting the requirements of engineering application
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Embodiment 1
[0020] The storage life of an exponential unit obeys the exponential distribution Exp(0.0002), the working life obeys the exponential distribution Exp(0.001), and the guaranteed task time T w =5000h, the number of spare parts S n is 8, try to calculate the number of spare parts loss N f Proceed as follows:
[0021] S1, initialization step
[0022] Let the current spare parts quantity S now =8,N f = 0, i = 1;
[0023] S2, cyclic calculation steps
[0024] S2.1, calculate the moment cT of the i-th warehouse inventory i
[0025]
[0026] S2.2, calculate the staged storage time Tzc
[0027] Since i=1, let Tzc=cT 1 =1835.8;
[0028] S2.3, Calculation of storage failure probability P z0
[0029] make
[0030] 2.4, update N f , S now
[0031] Order N f =N f +S now ×P z0 =2.46, let S now =max([(S now -1)×(1-P z0 )0])=4.85;
[0032] 2.5, let i=i+1=2, because i≤S n , so turn to step S2.1 and repeat the above steps;
[0033] When i=i+1=9, since i>S n , so ...
Embodiment 2
[0037] The storage life of an exponential unit obeys the exponential distribution Exp(0.0002), the working life obeys the exponential distribution Exp(0.001), and the guaranteed task time T w When =5000h, the number of spare parts k is 8, and the simulation process steps of the spare parts guarantee process with the risk of storage failure are as follows:
[0038] 1) The working time simTw=0 of the initialization unit;
[0039] 2) Generate a random number t 0 , used to simulate the working life of the unit in the equipment, t 0 obey the exponential distribution Exp(λ 2 ); let simTw=t 0 ;
[0040] 3) Generate k random numbers t1 m (1≤m≤k), used to simulate the storage life of spare parts, t1 m obey the exponential distribution Exp(λ 1 );
[0041] 4) Generate k random numbers t2 m (1≤m≤k), used to simulate the working life of spare parts, t2 m obey the exponential distribution Exp(λ 2 );
[0042] 5) Compare the size of simTw and Tw
[0043] If simTw>Tw, then this si...
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