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Weibull unit spare part demand quantity calculation method under storage failure risk

A Weibull-type, demand-based technology, applied in calculation, design optimization/simulation, special data processing applications, etc., can solve the problems of unsatisfactory spare parts storage environment, failure of guarantee tasks, and failure of spare parts, etc., to achieve fast and convenient calculation, The error is small and the effect of meeting the requirements of engineering applications

Active Publication Date: 2018-09-11
NAVAL UNIV OF ENG PLA
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  • Summary
  • Abstract
  • Description
  • Claims
  • Application Information

AI Technical Summary

Problems solved by technology

However, for those spare parts that are not usually stored in professional warehouses, such as random spare parts that are equipped with equipment, sometimes due to various conditions such as limited working environment and space, it is impossible to provide a storage environment for spare parts that meets the storage standards; especially for those long-term The equipment working in the field, such as the relevant equipment on the ship is at sea all the year round, and is often in a relatively harsh working environment such as high humidity, high salinity, mechanical and electrical equipment work or vibration caused by the shaking of the hull. If the working environment at this time If it is the storage environment of random spare parts, there is a risk of failure of spare parts during storage
At this time, if the risk of storage failure is ignored, and the conventional method is still used to calculate the demand for spare parts, the number of spare parts will be insufficient due to the failure of some spare parts during the storage period, which will lead to the failure of the support task

Method used

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  • Weibull unit spare part demand quantity calculation method under storage failure risk
  • Weibull unit spare part demand quantity calculation method under storage failure risk
  • Weibull unit spare part demand quantity calculation method under storage failure risk

Examples

Experimental program
Comparison scheme
Effect test

Embodiment 1

[0024] The storage life of a Weibull unit obeys the Weibull distribution W(4000,1.4), the working life obeys the Weibull distribution W(3000,1.6), and the guarantee task time T w =5000h, guarantee probability index P 0 is 0.85, try to calculate the demand for spare parts as follows:

[0025] S1, initialization step

[0026] S1.1, let the spare parts guarantee probability be

[0027] Because P ok 0 , so set the number of spare parts S = 1, go to step 1.2.

[0028] S1.2, let i=1, S now = S;

[0029] S2, calculate the guarantee probability P ok

[0030] S2.1, Calculate the failure probability gP 1 ,

[0031] make

[0032]

[0033] S2.2, calculate the fault time gT 1 ,make

[0034] S2.3, calculate storage effect Pzs

[0035] Since at this time S 1 = 1, so

[0036] S2.4, let P ok =P ok +gP 1 ×Pzs=0.3407, let S now =(S now -1)×(1-P z0 )=0;

[0037] S2.5, set i=i+1=2, since i>S, go to step 3.

[0038] S3, judgment step

[0039] Because at this time P ...

Embodiment 2

[0042] The storage life of a Weibull unit obeys the Weibull distribution W(4000,1.4), the working life obeys the Weibull distribution W(3000,1.6), and the guarantee task time T w =5000h, guarantee probability index P 0 is 0.85, try to calculate the demand for spare parts as follows:

[0043] 1) The working time simTw=0 of the initialization unit;

[0044] 2) Generate a random number t 0 , used to simulate the working life of the unit in the equipment, t 0 Obey the gamma distribution Ga(α 2 ,b 2 ); let simTw=t 0 ;

[0045] 3) Generate k random numbers t1 m (1≤m≤k), used to simulate the storage life of spare parts, t1 m Obey the gamma distribution Ga(α 1 ,b 1 );

[0046] 4) Generate k random numbers t2 m (1≤m≤k), used to simulate the working life of spare parts, t2 m Obey the gamma distribution Ga(α 2 ,b 2 );

[0047] 5) Compare the size of simTw and Tw.

[0048] If simTw>Tw, the task guarantee is successful, record simFlag=1;

[0049] If simTwm For spare parts...

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Abstract

The invention provides a Weibull unit spare part demand quantity calculation method under a storage failure risk. The method comprises the three steps of initialization, security probability calculation and judging. Calculation is accurate, the error is small, calculation is rapid and convenient, the result is close to an analogue simulation result of the executive condition of a traditionally adopted security task, and the engineering application requirements are met.

Description

technical field [0001] The invention relates to the field of calculation of demand for spare parts, in particular to a calculation method for demand of Weibull type unit spare parts under the risk of storage failure. Background technique [0002] Accurately calculating the demand for spare parts can quantitatively describe the degree of support of equipment from the perspective of economic costs such as spare parts procurement costs. [0003] "Spare parts are always "good" until they are put into use, and will not expire in storage" is a common assumption in all current spare part demand calculation methods. This assumption is reasonable if the spare parts are stored in professional warehouses with a good environment, and it is also very consistent with the actual performance of spare parts in reality. However, for those spare parts that are not usually stored in professional warehouses, such as random spare parts that are equipped with equipment, sometimes due to various c...

Claims

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Application Information

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Patent Type & Authority Applications(China)
IPC IPC(8): G06F17/50
CPCG06F2111/08G06F30/20
Inventor 张光宇任海东郭璇彭英武李华
Owner NAVAL UNIV OF ENG PLA
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