A method of inverse time zero-sequence current protection
A zero-sequence current, inverse-time technology, applied in emergency protection circuit devices, electrical components, etc., can solve the problem of low quickness, and achieve the goal of improving quickness, quickness and selectivity, and setting efficiency. Effect
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Embodiment 1
[0068] A method for inverse time zero-sequence current protection, the method comprising the following steps:
[0069] A. Establish the characteristic equation of inverse time zero-sequence current protection:
[0070]
[0071] In formula (1), t is the action time of inverse time-limit zero-sequence current protection, r, q, s are constants, 3I 0 is the zero-sequence current after a fault, I p It is the starting current of inverse time zero-sequence current protection; the value range of s is 0.1~1.9;
[0072] B. The maximum zero-sequence current after the line fault is 3I 0.max Substitute into formula (1) to determine the minimum action time t of the inverse time-lag zero-sequence current protection min :
[0073]
[0074] The starting current I of the inverse time zero-sequence current protection p Substitute into formula (1) to determine the maximum action time t of the inverse time-lag zero-sequence current protection max :
[0075]
[0076] t min with t ...
Embodiment 2
[0090] Basic content is the same as embodiment 1, the difference is:
[0091] When the selectivity of the main protection and the backup protection are mismatched, the longest action time T+t of the inverse time-lag zero-sequence current protection is increased by increasing the time difference T min , to ensure the rapidity and selectivity of protection.
[0092] Take Q=20, s=0.5, t min =0.05s, and calculate T=0.6s, T=1.0s and T=1.4s respectively, get as follows figure 2 The time-current characteristic curve of the inverse time zero-sequence current protection shown. From figure 2 It can be seen that with the increase of the time difference T, the action time of the inverse time limit protection will gradually increase.
[0093] I / I assumed to protect 1 P =8, I / I of protection 2 P =12, then when T=0.6s, the action time t of protection 1 1 =0.334s, action time t of protection 2 2 =0.224s, time interval △t=0.11s;
[0094] When T=1.0s, the action time of protection 1 ...
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