A kind of 2-amino-4,5-diarylthiazole type compound and its preparation method and application
A technology of thiazole type and compound, which is applied to 2-amino-4,5-diarylthiazole type compound and the field of preparation method and application thereof, can solve the problems of low bioavailability, drug resistance, high toxicity and the like, Achieving a good inhibitory effect
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Embodiment 1
[0029] Example 1: Preparation of 4-(5-methoxy-2,2-dimethyl-2H-benzopyran-8-yl)-5-phenylthiazol-2-amine (1)
[0030]
[0031] Step 1: Add 1-(2-hydroxy-4-methoxyphenyl)ethanone (4.85g, 10mmol) to 100mL CH 3 After CN was dissolved, cooled to 0°C in an ice bath, and slowly added DBU (1.5mL, 15mmol), CuCl 2 (4.03mg, 0.3%mmol), 3-chloro-3-methyl-1-butyne (1.53g, 15mmol), reacted in ice bath for 5h, TLC monitoring showed that the reaction was complete. Stop the reaction, add 1N dilute hydrochloric acid dropwise to adjust pH=2, remove CH under reduced pressure 3 CN, the residue was poured into 50mL water, a large amount of solids were precipitated, filtered, and dried as solid powder, the yield was 85%. 1 H NMR (d 6 -DMSO, 400 MHz) δ: 1.75 (s, 6H), 2.58 (s, 3H), 2.69(s, 1H), 3.84 (s, 3H), 6.58 (dd, 1H), 7.19 (d, 1H) , 7.75 (d, 1H); EIMS m / z =233.28 [M + ].
[0032] Step 2: Suspend 1-(4-methoxy-2-((2-methyl-3-yn-2-yl)oxo)phenyl)ethanone (2.32 g, 10 mmol) in 50 mL of pyridine ...
Embodiment 2
[0040] Example 2: Preparation of 5-phenyl-4-(2,2,5-trimethyl-2H-benzopyran-8-yl)thiazol-2-amine (2)
[0041]
[0042] The yield is 80%. 1 H NMR (d 6 -DMSO, 400 MHz) δ: 1.50 (s, 6H), 2.54 (s, 3H), 5.96(d, 1H), 6.67 (s, 2H), 6.79 (d, 1H), 6.88 (d, 1H), 7.42 (d, 1H), 7.45-7.56(m, 3H), 7.75-7.86(m, 2H); EIMS m / z = 349.46 [M + ].
Embodiment 3
[0043] Example 3: Preparation of 4-(5-ethyl-2,2-dimethyl-2H-benzopyran-8-yl)-5-phenylthiazol-2-amine (3)
[0044]
[0045] Yield 83%. 1 H NMR (d 6 -DMSO, 400 MHz) δ: 1.35 (t, 3H), 1.52 (s, 6H), 2.84(q, 2H), 5.98 (d, 1H), 6.83 (d, 1H), 6.87 (d, 1H), 6.97 (s, 2H), 7.43 (d,1H), 7.46-7.58 (m, 3H), 7.70-7.81 (m, 2H); EIMS m / z = 363.49 [M + ].
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