High-lubricity compound silicone oil for condom
A condom and lubricating technology, applied in the field of lubricating oil for condoms, can solve the problems of sexual intercourse pain, oily and easy to dry lubricating oil, unsatisfactory lubricating effect, etc., and achieve the effect of clear and transparent appearance and long-lasting lubricating performance
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example 1
[0012] Example 1: The determined target viscosity is n=1000mm 2 / s, the quality of the target lubricating oil is 10kg, that is, X1+X2=10kg, and the viscosity of low-viscosity silicone oil is n2=0.65mm 2 / s, the relationship between the viscosity n1 of high-viscosity silicone oil and the quality X1, X2 is as follows:
[0013] n1
X1
X2
10 million
4.34
5.56
5000000
4.62
5.38
3000000
4.78
5.22
1000000
4.84
5.16
500000
5.4
4.6
100,000
6.14
3.86
10000
7.6
2.4
0.5 million
8.2
1.8
[0014] In the above example, change n2 to 900m m 2 / s, other things remain unchanged, then the relationship between n1 and X1, X2 is as follows:
[0015] n1
example 2
[0016] Example 2, determine the target viscosity n = 500mm 2 / s, the quality of the target lubricating oil is 10kg, that is, X1+X2=10kg, the viscosity of low-viscosity silicone oil n2=0.65mm 2 / s, the relationship between the viscosity n1 of high-viscosity silicone oil and the quality X1, X2 is as follows:
[0017] n1
X1
X2
10 million
4.01
5.99
5000000
4.19
5.81
3000000
4.33
5.67
1000000
4.66
5.34
500000
4.9
5.1
100,000
5.58
4.42
10000
6.89
3.11
0.5 million
7.4
2.6
[0018] In this example, use n2=200m m instead 2 / s, and the rest remain unchanged, then the relationship between n1 and X1, X2 is as follows:
[0019] n1
example 3
[0020] Example 3: Determine the target viscosity n=200mm 2 / s. The target lubricating oil quality is 10kg, that is, X1+X2=10kg, and the viscosity of low-viscosity silicone oil n2=0.65, then the relationship between n1 and X1, X2 is as follows:
[0021] n1
X1
X2
10 million
3.4
6.6
5000000
3.6
6.4
3000000
3.7
6.3
1000000
4
6
500000
4.22
5.78
100,000
4.7
5.3
10000
6
4
0.5 million
6.4
3.6
[0022] In this example, use n2=100m m instead 2 / s, then the relationship between n1 and X1, X2 is as follows:
[0023] n1
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