Short-circuit fault ride-through and recovery method for direct current side of HVDC on basis of mixed type MMC
一种短路故障、恢复方法的技术,应用在交流功率输入变换为直流功率输出、电力传输交流网络、交流网络电压调整等方向,能够解决造价昂贵、高压大容量场合很少应用、技术不成熟等问题
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Embodiment 1
[0098] A short-circuit fault on the DC side is detected, and the DC voltage becomes 0kV; according to the stability requirements of the connected AC system and DC line, set the reference value of the active power transmitted by the hybrid MMC to 0MW, and the reactive power that needs to be injected into the AC system The reference value is 1MVAR, and the AC voltage reference value e required to be output by each phase of the MMC when the DC side short-circuit fault rides through is obtained iv_ref ; calculate u if_p , u ih_p , u if_n and u ih_n They are:
[0099] u if _ p = - e iv _ ref ( 1 - 1 2 m ) + U dc 1 4 ...
Embodiment 2
[0107] A short-circuit fault on the DC side is detected, and the DC voltage becomes 0kV; according to the stability requirements of the connected AC system and DC line, set the reference value of the active power transmitted by the hybrid MMC to 0MW, and the reactive power that needs to be injected into the AC system The reference value is 1MVAR, and the AC voltage reference value e required to be output by each phase of the MMC when the DC side short-circuit fault rides through is obtained iv_ref ; calculate u if_p , u ih_p , u if_n and u ih_n They are:
[0108] u if _ p = - 1 2 e iv _ ref - 1 4 U dc + 1 2 m U ...
Embodiment 3
[0116] A short-circuit fault on the DC side is detected, and the DC voltage becomes 0kV; according to the stability requirements of the connected AC system and DC line, set the reference value of the active power transmitted by the hybrid MMC to 0MW, and the reactive power that needs to be injected into the AC system The reference value is 1MVAR, and the AC voltage reference value e required to be output by each phase of the MMC when the DC side short-circuit fault rides through is obtained iv_ref ; calculate u if_p , u ih_p , u if_n and u ih_n They are:
[0117] u if _ p = - e iv _ ref ( 1 - x - 1 2 m + xm ) + ...
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