Transmission resource allocation method and equipment
A technology of transmission resources and allocation methods, applied in the field of transmission resource allocation methods and equipment, to achieve the effect of saving costs and reducing demand
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Embodiment 1
[0085] Take F(1) traffic as an example:
[0086](1) For an eNodeB that supports 3 cells, the uplink resource allocated by operation and maintenance at the S1 interface is V_F(1)=60Mbps due to the limited bandwidth, converted to V_Bytes_F(1)=60M*100ms / 8=750KBytes;
[0087] (2) QuotaF(1)[i]=750 / 3=250KBytes of each community at the beginning of M1, i takes a value of 1..3; M1 configures QuotaF(1)[i] to the M2 module of each community;
[0088] (3) After a period of 100ms, M2 reports to M1 that the actual sent data volumes of the three cells are 252Kbytes, 250Kbytes, and 150KBytes respectively; if deltaMin=5Kbytes, then A(k)={1, 2}; D(k)={ 3};
[0089] deltaF(1)[1]=252-250=2KBytes; this 2KBytes is caused by inaccurate estimation of headers by bandwidth usage modules such as MAC;
[0090] deltaF(1)[2]=deltaF(1)[3]=0;
[0091] Since 252+250+150<750, b=0;
[0092] (4) sumD(k)=250Kbytes-150Kbytes=100Kbytes, then
[0093] QuotaF(1)[1]=QuotaF(1)[2]=250+100 / 2=300KBytes;
[0094] Quo...
Embodiment 2
[0103] Take F(2) traffic as an example:
[0104] (1) For an eNodeB that supports 3 cells, the uplink resource allocated by operation and maintenance at the S1 interface due to bandwidth limitation is V_F(2)=6Mbps, converted to V_Bytes_F(2)=6M*100ms / 8=75KBytes;
[0105] (2) QuotaF(2)[i]=75 / 3=25KBytes of each community in M1 initial stage, i takes a value of 1..3; M1 configures QuotaF(1)[i] to the M2 module of each community;
[0106] (3) After a period of 100ms, M2 reports to M1 that the actual data volumes sent by the three cells are 26Kbytes, 28Kbytes, and 24KBytes respectively; if deltaMin=500Bytes, then A(k)={1, 2}; D(k)={ 3};
[0107] deltaF(2)[1]=26-25=1KBytes; deltaF(2)[2]=28-25=3KBytes; deltaF(2)[3]=0;
[0108] Since 26+28+24>75KBytes, b=1;
[0109] (4) M1 calculation: sumD(k)=25Kbytes-24Kbytes=1Kbytes, then
[0110] QuotaF(2)[1]=QuotaF(2)[2]=25+1 / 2=25.5KBytes;
[0111] QuotaF(2)[3]=24KBytes;
[0112] (5) M2 notifies M3 to set variable LeftScheBytesF(2)[i]=QuotaF(2...
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Abstract
Description
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Application Information
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